A Study Showed 118 Instances Of Breast Cancer

A study showed 118 instances of summit fecescer among 3,033 mothers who used diethylstilbestrol (DES), an estrogen-like shopping centre formerly used to prevent miscarriage, compared with 80 cases in 3,033 unexposed women comprising a control group (See Table 10.1). At the .01 level of significance, was the congener relative incidence of cancer greater in the DES users? control board 10.1 crabby person Study Results Statistic DES Takers Non-DES Takers Number of cancers x1 = 118 cancers x2 = 80 cancers Number of mothers n1 = 3,033 women n2 = 3,033 women cancer rate p1 = 118 p2 = 80 3,033= .03891 3,033= .02638 criterion 1: raise the Hypotheses Because it is surmise that DES increases the cancer risk, we will do a right-tailed riddle for equality of relations. We test only at the equality because rejecting H0: ?1 = ?2 would imply rejecting the entire screen out of hypotheses H0: ?1 ? ?2.We can state the pair of hypotheses in all of twain like ways: H0: ?1 = ?2 or H0: ?1 ?2 = 0 H1: ?1 > ?2 or H1: ?1 ?2 > 0 Step 2: State the Decision Rule At ? = .01 the right-tail critical nourish is z.01 = 2.

326, which yields the finish rule Reject H0 if z > 2.326 Otherwise do not reject H0 Step 3: Calculate the Test Statistic The screen out proportions indicate that DES-users have a higher incidence of breast cancer (.03 891) than non-DES users (.02638). We assume ! that ?1 = ?2 and peck if a contradiction stems from this assumption. assumptive that ?1= ?2, we can family the two samples to obtain a pooled estimate of the common proportion by dividing the unite number of breast cancer cases by the combined sample size: .p= x1 + x2 = 118 + 80 = 198 = .03264, or 3.26% n1 + n2 3,033 + 3,033 6,066 Assuming due north (i.e., large samples) the test statistic is z = p1 ? p2 _...If you wishing to get a full essay, order it on our website: OrderEssay.net

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